-4,9x^2+1x+25=0

Solution for -4,9x^2+1x+25=0 equation:

-4.9x^2+1x+25=0

We add all the numbers together, and all the variables

-4.9x^2+x+25=0

a = -4.9; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·(-4.9)·25
Δ = 491
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{491}=\sqrt{1*491}=\sqrt{1}*\sqrt{491}=1\sqrt{491}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1\sqrt{491}}{2*-4.9}=\frac{-1-1\sqrt{491}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1\sqrt{491}}{2*-4.9}=\frac{-1+1\sqrt{491}}{-9.8}
$